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Given the pattern "1/2/3/4" and the path "1/2/3/4/f", the pattern prefix is "1/2/3/4". We will compare and remove the prefix from both pattern and path and come to this code /* * If the whole pattern did not have a wildcard, * then our prefix match is all we need; we * do not need to call fnmatch at all. */ if (!patternlen && !namelen) return 1; where patternlen is zero (full pattern consumed) and the remaining path in "name" is "/f". We fail to realize it's matched in this case and fall back to fnmatch(), which also fails to catch it. Fix it. Signed-off-by: Nguyễn Thái Ngọc Duy <pclouds@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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