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fsck: make fsck_ident() warn-friendly
When fsck_ident() identifies a problem with the ident, it should still advance the pointer to the next line so that fsck can continue in the case of a mere warning. Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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Johannes Schindelin
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Junio C Hamano
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Jun 23, 2015
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