Documentation: unbreak regex in show-ref manual

I am not sure why, but the regular expression "(?:\^\{\})" gets rendered by asciidoc as "(?:\{})". The intent seems to be a regex matching the literal string "^{}", so this rewrites the markup to produce "(?:\^{})" as output. Cc: Julian Phillips <julian@quantumfyre.co.uk> Signed-off-by: Jonathan Nieder <jrnieder@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
git-mirror · Aug 20, 2010 · f100598 · f100598
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diff --git a/Documentation/asciidoc.conf b/Documentation/asciidoc.conf
@@ -16,6 +16,7 @@ plus=&#43;
 caret=&#94;
 startsb=&#91;
 endsb=&#93;
+backslash=&#92;
 tilde=&#126;
 apostrophe=&#39;
 backtick=&#96;

diff --git a/Documentation/git-show-ref.txt b/Documentation/git-show-ref.txt
@@ -73,8 +73,8 @@ OPTIONS
 --exclude-existing[=<pattern>]::
 
 	Make 'git show-ref' act as a filter that reads refs from stdin of the
-	form "^(?:<anything>\s)?<refname>(?:\^\{\})?$" and performs the
-	following actions on each:
+	form "^(?:<anything>\s)?<refname>(?:{backslash}{caret}\{\})?$"
+	and performs the following actions on each:
 	(1) strip "^{}" at the end of line if any;
 	(2) ignore if pattern is provided and does not head-match refname;
 	(3) warn if refname is not a well-formed refname and skip;