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Zhaolei
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Linus Torvalds
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Sep 24, 2009
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/* | ||
* Copyright (C) 1993, 1994, 1995, 1996, 1997 Free Software Foundation, Inc. | ||
* This file is part of the GNU C Library. | ||
* Contributed by Paul Eggert (eggert@twinsun.com). | ||
* | ||
* The GNU C Library is free software; you can redistribute it and/or | ||
* modify it under the terms of the GNU Library General Public License as | ||
* published by the Free Software Foundation; either version 2 of the | ||
* License, or (at your option) any later version. | ||
* | ||
* The GNU C Library is distributed in the hope that it will be useful, | ||
* but WITHOUT ANY WARRANTY; without even the implied warranty of | ||
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU | ||
* Library General Public License for more details. | ||
* | ||
* You should have received a copy of the GNU Library General Public | ||
* License along with the GNU C Library; see the file COPYING.LIB. If not, | ||
* write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330, | ||
* Boston, MA 02111-1307, USA. | ||
*/ | ||
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/* | ||
* Converts the calendar time to broken-down time representation | ||
* Based on code from glibc-2.6 | ||
* | ||
* 2009-7-14: | ||
* Moved from glibc-2.6 to kernel by Zhaolei<zhaolei@cn.fujitsu.com> | ||
*/ | ||
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#include <linux/time.h> | ||
#include <linux/module.h> | ||
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/* | ||
* Nonzero if YEAR is a leap year (every 4 years, | ||
* except every 100th isn't, and every 400th is). | ||
*/ | ||
static int __isleap(long year) | ||
{ | ||
return (year) % 4 == 0 && ((year) % 100 != 0 || (year) % 400 == 0); | ||
} | ||
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/* do a mathdiv for long type */ | ||
static long math_div(long a, long b) | ||
{ | ||
return a / b - (a % b < 0); | ||
} | ||
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/* How many leap years between y1 and y2, y1 must less or equal to y2 */ | ||
static long leaps_between(long y1, long y2) | ||
{ | ||
long leaps1 = math_div(y1 - 1, 4) - math_div(y1 - 1, 100) | ||
+ math_div(y1 - 1, 400); | ||
long leaps2 = math_div(y2 - 1, 4) - math_div(y2 - 1, 100) | ||
+ math_div(y2 - 1, 400); | ||
return leaps2 - leaps1; | ||
} | ||
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/* How many days come before each month (0-12). */ | ||
static const unsigned short __mon_yday[2][13] = { | ||
/* Normal years. */ | ||
{0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365}, | ||
/* Leap years. */ | ||
{0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335, 366} | ||
}; | ||
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#define SECS_PER_HOUR (60 * 60) | ||
#define SECS_PER_DAY (SECS_PER_HOUR * 24) | ||
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/** | ||
* time_to_tm - converts the calendar time to local broken-down time | ||
* | ||
* @totalsecs the number of seconds elapsed since 00:00:00 on January 1, 1970, | ||
* Coordinated Universal Time (UTC). | ||
* @offset offset seconds adding to totalsecs. | ||
* @result pointer to struct tm variable to receive broken-down time | ||
*/ | ||
void time_to_tm(time_t totalsecs, int offset, struct tm *result) | ||
{ | ||
long days, rem, y; | ||
const unsigned short *ip; | ||
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days = totalsecs / SECS_PER_DAY; | ||
rem = totalsecs % SECS_PER_DAY; | ||
rem += offset; | ||
while (rem < 0) { | ||
rem += SECS_PER_DAY; | ||
--days; | ||
} | ||
while (rem >= SECS_PER_DAY) { | ||
rem -= SECS_PER_DAY; | ||
++days; | ||
} | ||
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result->tm_hour = rem / SECS_PER_HOUR; | ||
rem %= SECS_PER_HOUR; | ||
result->tm_min = rem / 60; | ||
result->tm_sec = rem % 60; | ||
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/* January 1, 1970 was a Thursday. */ | ||
result->tm_wday = (4 + days) % 7; | ||
if (result->tm_wday < 0) | ||
result->tm_wday += 7; | ||
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y = 1970; | ||
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while (days < 0 || days >= (__isleap(y) ? 366 : 365)) { | ||
/* Guess a corrected year, assuming 365 days per year. */ | ||
long yg = y + math_div(days, 365); | ||
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/* Adjust DAYS and Y to match the guessed year. */ | ||
days -= (yg - y) * 365 + leaps_between(y, yg); | ||
y = yg; | ||
} | ||
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result->tm_year = y - 1900; | ||
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result->tm_yday = days; | ||
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ip = __mon_yday[__isleap(y)]; | ||
for (y = 11; days < ip[y]; y--) | ||
continue; | ||
days -= ip[y]; | ||
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result->tm_mon = y; | ||
result->tm_mday = days + 1; | ||
} | ||
EXPORT_SYMBOL(time_to_tm); |