---

yaml
---
r: 186203
b: refs/heads/master
c: da0aa13
h: refs/heads/master
i:
  186201: 15116d4
  186199: db3691c
v: v3

[refs]

@@ -1,2 +1,2 @@
 ---
-refs/heads/master: d96ae5309165d9ed7c008a178238977b73595cd9
+refs/heads/master: da0aa138944311e6745a00ac3d88f03e8d9a46c4

trunk/mm/mempolicy.c

@@ -888,36 +888,36 @@ int do_migrate_pages(struct mm_struct *mm,
 	if (err)
 		goto out;
 
-/*
- * Find a 'source' bit set in 'tmp' whose corresponding 'dest'
- * bit in 'to' is not also set in 'tmp'.  Clear the found 'source'
- * bit in 'tmp', and return that <source, dest> pair for migration.
- * The pair of nodemasks 'to' and 'from' define the map.
- *
- * If no pair of bits is found that way, fallback to picking some
- * pair of 'source' and 'dest' bits that are not the same.  If the
- * 'source' and 'dest' bits are the same, this represents a node
- * that will be migrating to itself, so no pages need move.
- *
- * If no bits are left in 'tmp', or if all remaining bits left
- * in 'tmp' correspond to the same bit in 'to', return false
- * (nothing left to migrate).
- *
- * This lets us pick a pair of nodes to migrate between, such that
- * if possible the dest node is not already occupied by some other
- * source node, minimizing the risk of overloading the memory on a
- * node that would happen if we migrated incoming memory to a node
- * before migrating outgoing memory source that same node.
- *
- * A single scan of tmp is sufficient.  As we go, we remember the
- * most recent <s, d> pair that moved (s != d).  If we find a pair
- * that not only moved, but what's better, moved to an empty slot
- * (d is not set in tmp), then we break out then, with that pair.
- * Otherwise when we finish scannng from_tmp, we at least have the
- * most recent <s, d> pair that moved.  If we get all the way through
- * the scan of tmp without finding any node that moved, much less
- * moved to an empty node, then there is nothing left worth migrating.
- */
+	/*
+	 * Find a 'source' bit set in 'tmp' whose corresponding 'dest'
+	 * bit in 'to' is not also set in 'tmp'.  Clear the found 'source'
+	 * bit in 'tmp', and return that <source, dest> pair for migration.
+	 * The pair of nodemasks 'to' and 'from' define the map.
+	 *
+	 * If no pair of bits is found that way, fallback to picking some
+	 * pair of 'source' and 'dest' bits that are not the same.  If the
+	 * 'source' and 'dest' bits are the same, this represents a node
+	 * that will be migrating to itself, so no pages need move.
+	 *
+	 * If no bits are left in 'tmp', or if all remaining bits left
+	 * in 'tmp' correspond to the same bit in 'to', return false
+	 * (nothing left to migrate).
+	 *
+	 * This lets us pick a pair of nodes to migrate between, such that
+	 * if possible the dest node is not already occupied by some other
+	 * source node, minimizing the risk of overloading the memory on a
+	 * node that would happen if we migrated incoming memory to a node
+	 * before migrating outgoing memory source that same node.
+	 *
+	 * A single scan of tmp is sufficient.  As we go, we remember the
+	 * most recent <s, d> pair that moved (s != d).  If we find a pair
+	 * that not only moved, but what's better, moved to an empty slot
+	 * (d is not set in tmp), then we break out then, with that pair.
+	 * Otherwise when we finish scannng from_tmp, we at least have the
+	 * most recent <s, d> pair that moved.  If we get all the way through
+	 * the scan of tmp without finding any node that moved, much less
+	 * moved to an empty node, then there is nothing left worth migrating.
+	 */
 
 	tmp = *from_nodes;
 	while (!nodes_empty(tmp)) {