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mtd: remove the de-select chip code in nand_release_device()
The nand_get_device() does not select the chip, but nand_release_device() does de-select the chip. It is really strange. With the current code, nand_sync() will de-select the chip, even if the chip has never been selected. To make the balance of select/de-select chip, it's better to remove the de-select chip code in nand_release_device() which makes the code more clear. Signed-off-by: Huang Shijie <b32955@freescale.com> Signed-off-by: Artem Bityutskiy <artem.bityutskiy@linux.intel.com>
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Huang Shijie
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Artem Bityutskiy
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Dec 3, 2012
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