x86/irq: Copy vectormask instead of an AND operation

In the case that the new vector mask is a subset of the existing mask there is
no point to do a AND operation of currentmask & newmask. The result is
newmask. So we can simply copy the new mask to the current mask and be done
with it. Preparatory patch for further consolidation.

Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Tested-by: Borislav Petkov <bp@alien8.de>
Tested-by: Joe Lawrence <joe.lawrence@stratus.com>
Cc: Jiang Liu <jiang.liu@linux.intel.com>
Cc: Jeremiah Mahler <jmmahler@gmail.com>
Cc: andy.shevchenko@gmail.com
Cc: Guenter Roeck <linux@roeck-us.net>
Cc: stable@vger.kernel.org #4.3+
Link: http://lkml.kernel.org/r/20151231160106.640253454@linutronix.de
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>

arch/x86/kernel/apic/vector.c

@@ -156,7 +156,7 @@ static int __assign_irq_vector(int irq, struct apic_chip_data *d,
 				       vector_cpumask);
 			d->move_in_progress =
 			   cpumask_intersects(d->old_domain, cpu_online_mask);
-			cpumask_and(d->domain, d->domain, vector_cpumask);
+			cpumask_copy(d->domain, vector_cpumask);
 			goto success;
 		}