x86/efi: Remove the always true EFI_DEBUG symbol

This symbol is always set which makes it useless. Additionally we have
a kernel command-line switch, efi=debug, which actually controls the
printing of the memory map.

Reported-by: Robert Elliott <elliott@hpe.com>
Signed-off-by: Matt Fleming <matt@codeblueprint.co.uk>
Acked-by: Borislav Petkov <bp@suse.de>
Cc: Ard Biesheuvel <ard.biesheuvel@linaro.org>
Cc: Borislav Petkov <bp@alien8.de>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: linux-efi@vger.kernel.org
Link: http://lkml.kernel.org/r/1461614832-17633-16-git-send-email-matt@codeblueprint.co.uk
Signed-off-by: Ingo Molnar <mingo@kernel.org>

arch/x86/platform/efi/efi.c

@@ -54,8 +54,6 @@
 #include <asm/rtc.h>
 #include <asm/uv/uv.h>
 
-#define EFI_DEBUG
-
 static struct efi efi_phys __initdata;
 static efi_system_table_t efi_systab __initdata;
 
@@ -222,7 +220,6 @@ int __init efi_memblock_x86_reserve_range(void)
 
 void __init efi_print_memmap(void)
 {
-#ifdef EFI_DEBUG
 	efi_memory_desc_t *md;
 	int i = 0;
 
@@ -235,7 +232,6 @@ void __init efi_print_memmap(void)
 			md->phys_addr + (md->num_pages << EFI_PAGE_SHIFT) - 1,
 			(md->num_pages >> (20 - EFI_PAGE_SHIFT)));
 	}
-#endif  /*  EFI_DEBUG  */
 }
 
 void __init efi_unmap_memmap(void)