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Rather than using a C implementation of memset, directly call memset,…
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… which

typically has a much faster optimized implementation.
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Wilco Dijkstra committed Feb 27, 2015
1 parent 49f476f commit ddcf679
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4 changes: 4 additions & 0 deletions ChangeLog
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2015-02-27 Wilco Dijkstra wdijkstr@arm.com

* string/bzero.c (__bzero): Call memset for performance.

2015-02-27 John David Anglin <dave.anglin@bell.net>

* sysdeps/unix/sysv/linux/hppa/bits/fcntl.h (__O_SYNC): Change
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57 changes: 2 additions & 55 deletions string/bzero.c
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Expand Up @@ -17,66 +17,13 @@
<http://www.gnu.org/licenses/>. */

#include <string.h>
#include <memcopy.h>

#undef __bzero

/* Set N bytes of S to 0. */
void
__bzero (s, len)
void *s;
size_t len;
__bzero (void *s, size_t len)
{
long int dstp = (long int) s;
const op_t zero = 0;

if (len >= 8)
{
size_t xlen;

/* There are at least some bytes to zero. No need to test
for LEN == 0 in this alignment loop. */
while (dstp % OPSIZ != 0)
{
((byte *) dstp)[0] = 0;
dstp += 1;
len -= 1;
}

/* Write 8 op_t per iteration until less than 8 op_t remain. */
xlen = len / (OPSIZ * 8);
while (xlen != 0)
{
((op_t *) dstp)[0] = zero;
((op_t *) dstp)[1] = zero;
((op_t *) dstp)[2] = zero;
((op_t *) dstp)[3] = zero;
((op_t *) dstp)[4] = zero;
((op_t *) dstp)[5] = zero;
((op_t *) dstp)[6] = zero;
((op_t *) dstp)[7] = zero;
dstp += 8 * OPSIZ;
xlen -= 1;
}
len %= OPSIZ * 8;

/* Write 1 op_t per iteration until less than op_t remain. */
xlen = len / OPSIZ;
while (xlen != 0)
{
((op_t *) dstp)[0] = zero;
dstp += OPSIZ;
xlen -= 1;
}
len %= OPSIZ;
}

/* Write the last few bytes. */
while (len != 0)
{
((byte *) dstp)[0] = 0;
dstp += 1;
len -= 1;
}
memset (s, '\0', len);
}
weak_alias (__bzero, bzero)

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